72x^2-96=0

Solution for 72x^2-96=0 equation:

72x^2-96=0

a = 72; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·72·(-96)
Δ = 27648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{27648}=\sqrt{9216*3}=\sqrt{9216}*\sqrt{3}=96\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96\sqrt{3}}{2*72}=\frac{0-96\sqrt{3}}{144}
=-\frac{96\sqrt{3}}{144}
=-\frac{2\sqrt{3}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96\sqrt{3}}{2*72}=\frac{0+96\sqrt{3}}{144}
=\frac{96\sqrt{3}}{144}
=\frac{2\sqrt{3}}{3}
$